Today's example is about actual solution of Cube root using abacus.
Today's example is simple - basic 1/3-multiplication table method, root is 2-digits case. You can check the Index page of all articles.
Cube root methods: Triple-root method, constant number method, 3a^2 method, 1/3-division method, 1/3-multiplication table method, 1/3-multiplication table alternative method, Multiplication-Subtraction method, 3-root^2 method, Mixing method, Exceed number method, Omission Method, etc.
Abacus steps to solve Cube root of 474,552
(Answer is 78)
"1st group number" is the left most numbers in the 3-digits groups of the given number for cube root calculation. Number of groups is the number of digits of the Cube root.
474,552 -> (474|552): 474 is the 1st group number. The root digits is 2.
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Step 1: Place 474552 on GHIJKL.
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Step 2: The 1st group is 474.
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Step 3: Cube number ≦ 474 is 343=7^3. Place 7 on C as the 1st root.
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Step 4: Subtract 7^3 from the 1st group 474. Place 474-7^3=131 on GHI.
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Step 5: Focus on 131552 on GHIJKL.
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Step 6: Divide 131552 by 3. Place 131552/3=043850.6をGHIJKLM.
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Step 7: Focus on 43 on HI.
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Step 8: Repeat division by triple root 7 until 4th digits next to 1st root. 43/7=6 remainder 1. Place 6 on E as 2nd root.
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Step 9: Place remainder 01 on HI.
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Step 10: Divide 18 on IJ by current root 7. 18/7=2 remainder 4
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Step 11: Place 2 on F.
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Step 12: Place 04 on IJ.
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Step 13: Divide 45 on JK by current root 7. 45/7=6 remainder 3
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Step 14: Place 6 on G.
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Step 15: Place 03 on JK.
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Step 16: Divide 62 on EF by current root 7. 62/7=8 remainder 2
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Step 17: Place 8 on D as 2nd root.
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Step 18: Place 06 on EF.
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Step 19: Subtract 2nd root^2 from 66 on FG. 66-8^2=2
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Step 20: Place 02 on FG.
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Step 21: 02 on FG x 1st root and add 03.0 on JKL. 2X7+3.0=17.0
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Step 22: Place 17.0 on JKL.
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Step 23: Subtract 2nd root^3/3 from 170.6 on JKLM. 170.6-8^3/3=0
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Step 24: Place 000.0 on JKLM.
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Step 25: Cube root of 474552 is 78.
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Final state: Answer 78
Following the last time, today's example is about actual solution of Cube root using abacus.
Today's example is simple - basic 1/3-multiplication table method, root is 2-digits case. You can check the Index page of all articles.
Cube root methods: Triple-root method, constant number method, 3a^2 method, 1/3-division method, 1/3-multiplication table method, 1/3-multiplication table alternative method, Multiplication-Subtraction method, 3-root^2 method, Mixing method, Exceed number method, Omission Method, etc.
Abacus steps to solve Cube root of 421,875
(Answer is 75)
"1st group number" is the left most numbers in the 3-digits groups of the given number for cube root calculation. Number of groups is the number of digits of the Cube root.
421,875 -> (421|875): 421 is the 1st group number. The root digits is 2.
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Step 1: Place 421875 on GHIJKL.
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Step 2: The 1st group is 421.
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Step 3: Cube number ≦ 421 is 343=7^3. Place 7 on C as the 1st root.
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Step 4: Subtract 7^3 from the 1st group 421. Place 421-7^3=078 on GHI.
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Step 5: Focus on 78875 on HIJKL.
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Step 6: Divide 78875 by 3. Place 78875/3=26291.6 on HIJKLM.
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Step 7: Focus on 26 on HI.
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Step 8: Repeat division by triple root 7 until 4th digits next to 1st root. 26/7=3 remainder 5. Place 3 on E.
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Step 9: Place remainder 05 on HI.
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Step 10: Divide 52 on IJ by current root 7. 52/7=7 remainder 3
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Step 11: Place 7 on F.
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Step 12: Place 03 on IJ.
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Step 13: Divide 39 on JK by current root 7. 39/7=5 remainder 4
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Step 14: Place 5 on G.
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Step 15: Place 04 on JK.
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Step 16: Divide 37 on EF by current root 7. 37/7=5 remainder 2
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Step 17: Place 5 on D as 2nd root.
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Step 18: Place 02 on EF.
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Step 19: Subtract 2nd root^2 from 25 on FG. 25-5^2=0
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Step 20: Place 00 on FG.
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Step 21: 00 on FG x 1st root and add 04.1 on JKL. 0X7+4.1=4.1
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Step 22: Place 04.1 on JKL. It means do nothing.
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Step 23: Subtract 2nd root^3/3 from 41.6 on KLM. 41.6-5^3/3=0
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Step 24: Place 00.0 on KLM.
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Step 25: Cube root of 421875 is 75.
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Final state: Answer 75
Joseph Polchinski: 2015 Breakthrough Prize in Fundamental Physics Symposium
(動画検索)
昨年8月にお書きになった博士による自伝が、ここに公開されています。
Memories of a Theoretical Physicist
Joseph Polchinski
(Submitted on 30 Aug 2017 (v1), last revised 31 Aug 2017 (this version, v2)) https://arxiv.org/abs/1708.09093